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8w=2w^2-16w
We move all terms to the left:
8w-(2w^2-16w)=0
We get rid of parentheses
-2w^2+8w+16w=0
We add all the numbers together, and all the variables
-2w^2+24w=0
a = -2; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-2)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-2}=\frac{-48}{-4} =+12 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-2}=\frac{0}{-4} =0 $
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